(Untitled)

[alison_in_oh]

This is why I hate doing the math to construct a soaker from scratch, and am trying to write up the pattern so I never have to do it again.

I usually do trial and error to a point and then jimmy some figures so they work. This time I'm trying to be more methodical about it so I've come up with a system of equations to solve.

Comments

[breakableheart]

::waits for erin::

[alison_in_oh]

Because a has a limited range of feasible results, from about 5 to about 8, I think I'm just going to treat it as a parameter and solve for k given varied values of a.

[alison_in_oh]

Wait, no. Define k in the second equation in terms of a. Then solve for the closest fit? Hrm.

[alison_in_oh]

For there to BE a solution a has to be greater than 7.

[alison_in_oh]

OK, if a is 7, then k is 1.26. If a is 8, then k is 1.54. This puts the hypoteneuse at 7.41 or 6.94 respectively. Which is patently impossible just from looking at it. Crap. Back to the drawing board.

[alison_in_oh]

I think you need some crazy-ass solving methods that I've forgotten, because of the root. You can't get rid of it, the quadratic expansion just plonks it right back into the middle term.

I'm knitting a soaker, and at the point where the legs split for front and back. I'm balancing the need to make the leg opening fit the thigh and the length fit the rise measurement. a is the number of stitches to bind off at each side. k is the length in inches to knit even after finishing the decreases to the crotch width.

*head explodey*

I think I need to change some of my base assumptions, like the rise at which I'm going to start the split and decreases...

[alison_in_oh]

Wait, I'm a complete morone, of course you can get rid of the root if you isolate it on one side of the equation before squaring. GAH. Please let me save two brain cells through to the end of nursing? They'll be lonely if I get down to just one. *whimper*