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nozomiwhitewolf
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anti_chemistry
Woe is me...
Mar 21, 2006 18:22
Must complete 2 AP exams (1999 exam and 2001 exam) for Friday. I am currently on the first problem of the 1999 exam (its SO long...) and I am stuck already. =( I don't know what to do for some of these as we never really learned it (
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cowbert
March 22 2006, 00:19:55 UTC
Kb = [NH4+][OH-]/[NH3]
Since you have [NH3], you can solve for [NH4+]. Then you take the ratio of [NH4+]/[NH3] * 100%.
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Comments 1
Since you have [NH3], you can solve for [NH4+]. Then you take the ratio of [NH4+]/[NH3] * 100%.
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