Finding the roots of a quadratic equation with leading coefficient greater than 1
When the amphibious boat full of drunk tourists drives up state yelling with joy i wave
then i put out my cigarettes and go back to coffee and math
i need to quit smoking... it's pretty stupid by now
straight retarded that i still smoke, really
4y^2 + 20y= -25
4y^2 + 20y + 25 = 0 //4*25=100=10*10
4y^2 + 10y + 10y + 25 = 0 //10+10=20
2y(2y + 5) + 5(2y + 5)
(2y + 5)(2y + 5) = 0
y = -5/2
4z^2 = -12z - 9
4z^2 + 12z + 9 = 0 //4*9=36=6*6
4z^2 + 6z + 6z + 9 = 0 //6z+6z=12z
2z(2z+3) + 3(2z+3) = 0
(2z+3)(2z+3)=0
2z+3=0
2z=-3
z=-3/2
then i put out my cigarettes and go back to coffee and math
i need to quit smoking... it's pretty stupid by now
straight retarded that i still smoke, really
4y^2 + 20y= -25
4y^2 + 20y + 25 = 0 //4*25=100=10*10
4y^2 + 10y + 10y + 25 = 0 //10+10=20
2y(2y + 5) + 5(2y + 5)
(2y + 5)(2y + 5) = 0
y = -5/2
4z^2 = -12z - 9
4z^2 + 12z + 9 = 0 //4*9=36=6*6
4z^2 + 6z + 6z + 9 = 0 //6z+6z=12z
2z(2z+3) + 3(2z+3) = 0
(2z+3)(2z+3)=0
2z+3=0
2z=-3
z=-3/2