My cousin asked me this question some time back. The question was taken form a bridging module for university maths in states. I think it is equivalent to JC maths H2/H3 here in singapore. The thing is, those who claimed to be pro in maths, should try this. hiak hiak...
Question: Find the value of x from the equation
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Using the formula arctan(x) + arctan(y) = arctan[(x+y)/(1-xy)],
arctan(6/x) + arctan(1/x)
= arctan[(7/x)/(1-6/x^2)]
= arctan[7x/(x^2-6)]
Taking tan on both sides of the original equation,
7x/(x^2-6) = tan(pi/6) = 1/sqrt(3)
Thus x^2 - 7sqrt(3)x + 6 = 0
and can be solved using quadratic formula which I'm too lazy to do.
QED. :P
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fwahhh.. both so smart! =p
hmm.. so when u wan ur kissh? *blush*
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reject my kiss siah.. kaoz ~~~
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