(Untitled)

[brightmoonshade]

math question for you

Comments

[ivegotyournose]

"The trick to this riddle is that the addition and subtraction are done at the wrong times to misdirect your thinking - and quite successfully for most. Each of the 3 friends did indeed pay $9, not $10, and as far as the friends are concerned, they paid $27 for the night. But we know that the clerk will tell us that they were charged only $25 and when you add the $3 returned with the $2 kept by the bellhop, you come up with $30."

[brightmoonshade]

that doesnt solve the math problem though. the guys still payed 27 dollars and the bellhop only had 2. where is the other dollar????

[iscareboys]

BLEH. you guys are bigger nerds than me! ;)

JK. WE all know that's not possible!!!

[rick_darris]

ok it is hard to explain but the extra dollar is getting mixed up wiht the 2 dollars the bellhop has. so look at it this way: at the end the owner has $25, the Bellhop has $2, first person has $1, the second has $1, and the third has $1, add it u[p at the end and you get $30, they did not pay nine dollars they payed $10. i hope that makes since to you.

[brightmoonshade]

you are just refrasing it too i think. mrs koger couldnt figure it out either. so who knows