(Untitled)

Jul 11, 2007 17:17

so, i found something interesting in my econ book and i wanted to know if it was always true

notation
let [a,b] = the closed interval from a to b
let (integral r) phi = the integral over the interval r of the function phi
let d = lim (epsilon->0+) delta

given a function f over Rlet g(x) = ( (integral [zero, x]) f(t) * dt ) / x ( Read more... )

calculus, untagged, math, proof, economics

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Comments 6

calcnerd256 July 11 2007, 22:37:17 UTC
note the past tense on "wanted"
i proved it, so don't worry about telling me it's always true
it's as true as the leaves on the proof tree (not shown)

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calcnerd256 July 12 2007, 01:53:06 UTC
okay, i know why it's true now
f represents the values being pumped into the numerator
x is the denominator
so it's like gpa
if f > g, g' > 0
etc etc mutatis mutare

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calcnerd256 July 12 2007, 01:55:55 UTC
that's mutatis mutandis, i think
i'll ask courtney

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calcnerd256 July 12 2007, 02:05:45 UTC
so that means there exists a phi such that
phi(x) < 0 <=> x < 0
phi(0) = 0
phi(x) > 0 <=> x > 0
g'(x) = phi((f - g)(x))

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calcnerd256 November 24 2007, 19:16:45 UTC
so that means there exists a φ such that
φ(x) < 0 <=> x < 0
φ(0) = 0
φ(x) > 0 <=> x > 0
g'(x) = φ((f - g)(x))

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