Notice that 8 is the same as 2^3. Also notice that 1/2 is 2^-1. When we have bases that are the same, we can set the exponents equal to one another.
So, referring to the first one, 2^3(x^2 - 2x) = 2^-1. So, multiplying the 3 through, we get 3x^2 - 6x = -1, or 3x^2 - 6x + 1 = 0. Solve as you normally would a quadratic. (Quadratic formula, complete the square, etc.)
Try the above with the second problem also. Make the bases the same is the key.
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Also, if you look downward in the community, you'll see a bunch of posts about logarithms. those posts should point you in the right direction
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So, referring to the first one, 2^3(x^2 - 2x) = 2^-1. So, multiplying the 3 through, we get 3x^2 - 6x = -1, or 3x^2 - 6x + 1 = 0. Solve as you normally would a quadratic. (Quadratic formula, complete the square, etc.)
Try the above with the second problem also. Make the bases the same is the key.
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where is your icon from?
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Haha, and that is a pretty cool icon, especially since 'Here comes the sun' is a song by the Beatles, and I'm going to listen to it now. XD
Niiiiiiice. =D
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