centroid of a semi ellipse

Mar 03, 2007 21:07

I've been working on this problem for 3+ hours, and with an English term paper due on Monday, I give up. Help!

The QuestionFind the centroid of the semi-elliptical region defined by ( Read more... )

Leave a comment

Comments 4

profhauke March 4 2007, 15:34:01 UTC
When I look at your integral, it seems you're multiplying x by the equation for the top half of the region you're interested in, so you'd be finding the centroid of the upper right quarter of the ellipse (where x>0 and y>0) not the centroid of the right half of the ellipse (where just x>0).

As to how to do it, what's the derivative of u = 1-(x/a)^2?

Reply

saaraneth March 5 2007, 00:59:36 UTC
oh. So to find it for the right half of the ellipse, where x>0...do I multiply the b*sqaureRoot(1-(x/a)) by 2?

the derivative of u = 1-(x/a)^2 should be du/dx=-(2/a^2)x or is it something to do with trig because I'm bad at that?

thanks for your help. =D

Reply

profhauke March 5 2007, 01:31:33 UTC
Yes, you'd multiply by 2. Also, I was trying to hint at a u substitution you might try, without giving it away totally. Do you see how it'd work?

Reply

saaraneth March 5 2007, 02:13:02 UTC
Oh wow. I got it. Thank you so much!

Reply


Leave a comment

Up