HELP Integral

Apr 22, 2007 19:59

But I'm pretty new to calculus and I'm trying to teach myself how to do an integral because my math teacher confused the hell out of me the other day.

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joshua_green April 23 2007, 01:12:42 UTC
You could always expand the polynomial before integrating.
You erred when you just replaced the dx by du.  The original integral has dx and, since u = 1 - 3x, du/dx = -3, so dx = -du/3.

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joshua_green April 23 2007, 01:19:02 UTC
Therefore, you shouldn't get 2∫u2du, but should instead get 2∫u2(-du/3)

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xiaa April 23 2007, 02:28:18 UTC
So, I can't change the dx to a du, so I do it like this?


... )

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joshua_green April 23 2007, 03:03:54 UTC
Yes, that's all true, though I would think that you'd rather convert everything to u's (your final expression is exactly what you began with).

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anonymous April 23 2007, 01:16:31 UTC
I found your problem..I think.

In order for you to substitute your integral into the "u^n du" form, here you set du equal to -3dx, which is correct but.. in making the substitution work, you've altered the value of the integral, so you have to divide by -3 outside the integral too so that you're really just multiplying by 1.

Hopefully someone else can leave you an answer that's more comprehensive.

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