You could always expand the polynomial before integrating. You erred when you just replaced the dx by du. The original integral has dx and, since u = 1 - 3x, du/dx = -3, so dx = -du/3.
In order for you to substitute your integral into the "u^n du" form, here you set du equal to -3dx, which is correct but.. in making the substitution work, you've altered the value of the integral, so you have to divide by -3 outside the integral too so that you're really just multiplying by 1.
Hopefully someone else can leave you an answer that's more comprehensive.
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You erred when you just replaced the dx by du. The original integral has dx and, since u = 1 - 3x, du/dx = -3, so dx = -du/3.
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In order for you to substitute your integral into the "u^n du" form, here you set du equal to -3dx, which is correct but.. in making the substitution work, you've altered the value of the integral, so you have to divide by -3 outside the integral too so that you're really just multiplying by 1.
Hopefully someone else can leave you an answer that's more comprehensive.
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