So, I have a calculus question on hand about double integrals and volume. It's a practice problem without any solution, so I was wondering if people could give input
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You want to integrate 2xy over the first quadrant of the unit circle. We start by noticing that x = rcosQ, y = rsinQ. So to integrate over the unit circle, we integrate from Q = 0 to Q = pi/2 and the radius goes from r = 0 to r = 1. Then, what we integrate is... 2r^2cosQsinQ*r drdQ. Be sure to remember the Jacobian r that goes with dQ.
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We start by noticing that
x = rcosQ,
y = rsinQ.
So to integrate over the unit circle, we integrate from Q = 0 to Q = pi/2 and the radius goes from r = 0 to r = 1.
Then, what we integrate is...
2r^2cosQsinQ*r drdQ. Be sure to remember the Jacobian r that goes with dQ.
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Because I have double integrals from 0-1, 0-sqrt(1-x^2) of 2xy dydx.
I ended up with 1/4units cubed.
That can't be right
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And why can't 1/4 units cubed be right? ;)
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