Reaction Rates

[jinx24]

Hey, I was wondering if anyone could help me with a problem regarding reaction rates

For the following reaction in a 4.00-L container, it was found that 1.00 x 10-4 mol of C4H8 reacted over a time period from 10:58 A.M. to 11:15 A.M.

C4H8 (g) --> 2C2H4 (g

Comments

[lurel]

There's some error in your math. If you divide 1.00 x 10^-4 mol by 4.00 L to get the molarity, you should get 0.000025 M. Then, 0.000025 M divided by 1020 s should result in 2.45 x 10^-8.

Hope that helps.

[jinx24]

Ooooh, I see what I did wrong now.

Thanks !!