Getting (too) involved with i

Aug 15, 2007 10:08

I like i. It was exciting indeed to discover i, and from my first exposure to i, I found myself infatuated. i is a delightful thing to explore! When things are rough, I can count on i to help me get to the root of the problem, and when it's just me and only i, of course, things are never truly negative. It's odd, but when I am at peace with i and ( Read more... )

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Comments 21

szibarita August 15 2007, 18:09:06 UTC
oh god, i really wish i knew what you were talking about

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echo_eriol August 15 2007, 18:13:06 UTC
i is an imaginary number, the square root of -1. So, i^2 is -1, i^3 is -i, and i^4 is 1.

An iamb is a rythmic "foot" used in poetry where an unstressed syllable is followed by a stressed syllable: da DUM da DUM da DUM.

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misanthropicsob August 15 2007, 19:10:45 UTC
Stop playing with i!!! They will bring you to no good. And, play gently. You don't want to poke your is out.

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echo_eriol August 16 2007, 17:58:19 UTC
It's ok. i is imaginary. It can only poke my mental eye.

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zorpo August 15 2007, 21:58:50 UTC
I believe that this post is about masturbation, and I'm not changing my mind.

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echo_eriol August 16 2007, 17:57:17 UTC
OK...fighting urge to reply with innappropriate entenndre...fighting...

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i? zorpo August 24 2007, 15:19:57 UTC
-1 = -1
i^2 = i^2; mutliply both sides by 1 (in different forms)
i^2 x i^4 = i^2 x 1
i^6 = i^2; take the roots
(i^6)^0.5 = (i^2)^0.5
i^3 = i; divide by i
i^2 = 1
-1 = 1

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Re: i? zorpo August 29 2007, 18:06:22 UTC
There's an error in there, but I do know there was a proof for this.
Anyone know it?

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