Something that's bugged me for a long time is this:
How many paths, starting at the origin, taking N steps either up, down, left or right, end up at a particular place (x, y)? Ignoring the fact that x+y has to have the same parity as N, something that goes like e- k(x2 + y2), right? Just central-limit-type reasoning ought to suffice to see that.
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Simplicius says: Given a path, if you're willing to compute its sum, you can then tweak one or two steps of the path to get your (x,y)' instead.
But that's not satisfactory, because it doesn't seem like you should have to do that?
Simplicius says: wolog say we start with an E (1, 0) that we're rotating alpha c.c.w. The rotated (cos, sin) should be our expectation, and we want to give probabilities on NESW that yield that expectation. Can't do that by blending just E and N, obviously, that just gives a straight line interpolant that falls inside the circle. But we can do it by blending E, N, and E+N.
Is that allowed, to rotate E to EN sometimes? Because it does seem like you're going to have to.
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Changing the length of the path as it rotates a little bit seems acceptable, as long as the length changes average out to nothing over the long run, and/or is negligible for long paths.
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Backing up -- to me the rotational symmetry is not the basic thing here, the Gaussianness is. (You can twiddle the setup to get a Gaussian ellipsoid.) In one dimension, the Gaussianness is born out of the 2^n paths at the point where you sum them down to get the (n choose k) line, where you diagonally scan the n-cube. The multidimensional Gaussian comes together in the usual way.
Of course this assumes some properties of Gaussians which you may be preferring to roll your own intuition of?
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