So, in the case of N = 1 (base case), you will do 0 (1-1) of them, and have one left.
Assuming that for N-1, you will have 1 thing to do and thus not be finished, Adding 1 to both sides gives you N, but then you will do 1 thing, still leaving you with 1 thing.
Exactly! Fortunately though, I can trick myself into including extraneous values into the set of N. Example: cleaning my room. If I have one homework assignment left and I convince myself that I really need to clean my room, I can do the homework assignment under the pretense that I'm avoiding cleaning my room.
Basically I play mind games with myself. Usually I lose.
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Assuming that for N-1, you will have 1 thing to do and thus not be finished, Adding 1 to both sides gives you N, but then you will do 1 thing, still leaving you with 1 thing.
Thus, you will never be finished. QED.
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Basically I play mind games with myself. Usually I lose.
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