Puzzle
I've been toying with a puzzle to (possibly) use at work and thought I'd try it out on you, my adoring public.
A and B have exactly three English coins in common circulation each (i.e. some of 1p, 2p, 5p, 10p, 20p, 50p, £1, £2). They have the same amount of money but different sets of coins. How much money does each of them have if:
1) All six coins are silver (5p, 10p, 20p or 50p)
2) None of the coins are silver
3) C and D also have two different sets of three coins each adding up to twice as much as A or B's total and neither A nor B has three coins of the same value.
Each one has a unique answer. The first person to successfully solve all three wins a prize equivalent to the smallest amount of money A could have.
Please note that the enumeration of the values of coins is not because I think any of you are stupid but because many of you are smart arses who will point out that I've omitted the 1976 £5.25 silver commemorative "five guinea" piece or somesuch.
A and B have exactly three English coins in common circulation each (i.e. some of 1p, 2p, 5p, 10p, 20p, 50p, £1, £2). They have the same amount of money but different sets of coins. How much money does each of them have if:
1) All six coins are silver (5p, 10p, 20p or 50p)
2) None of the coins are silver
3) C and D also have two different sets of three coins each adding up to twice as much as A or B's total and neither A nor B has three coins of the same value.
Each one has a unique answer. The first person to successfully solve all three wins a prize equivalent to the smallest amount of money A could have.
Please note that the enumeration of the values of coins is not because I think any of you are stupid but because many of you are smart arses who will point out that I've omitted the 1976 £5.25 silver commemorative "five guinea" piece or somesuch.