Function with 90 degree rotational symmetry about the origin?

Nov 12, 2012 10:20

I haven't done calculus level math in a long time, and this question has got me stumped ( Read more... )

function, calculus, graphing

Leave a comment

Comments 6

phlebas November 12 2012, 16:16:27 UTC
Presumably you mean the graph has 90 degree rotational symmetry about the origin.
Does it help if you work out what that means in terms of the function itself?
f(0)=0
f(-x)=-f(x)
and so on.
It sounds like something where the exact wording of the question could matter - do you have a more precise formulation, or do you know whether you should assume some form of the axiom of choice for the construction?

Reply

lackasexical November 12 2012, 16:48:36 UTC
Well, we did get to this point:


... )

Reply

phlebas November 12 2012, 16:54:45 UTC
Assuming what you have works (you'll need to tweak a couple of inequalities, but something along those lines sounds good) you can just define f(0)=0, yes. Then prove that it satisfies the conditions and you're done.

Reply

lackasexical November 12 2012, 17:27:22 UTC
Ah, you're right, there were some opportunities for missing points with those inequalities!

We've adjusted it like so:


... )

Reply


Leave a comment

Up