Something I'm getting to hate in KenKen

[nellherself]

Three cells whose product is 60

Comments

[le_trombone]

Ah, the old 3-4 vs. 2-6 problem.

Tough. Work out the other cages.

(Also, if possible, take advantage of the sum(1..n) formula. It's saved me from some hairy calculations more than once.)

[nellherself]

And I'm not to fond of three cells with a product of 12 either.

Sum (1...n) does help quite a bit especially finding the correct roots of something unpardonably vicious like 5 adjacent cells whose product is 3780.