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Dec 14, 2006 11:56

1 = 0.999 recurring

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Comments 31

mr_cullen December 14 2006, 12:44:44 UTC
Divide by Zero? D:

I never was good with numbers.

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schivnorr December 14 2006, 14:09:25 UTC
Yes. Exactly.

Let x = 0.999 recurring.
Then, 10*x = 9.999 recurring.

10*x - x = 9*x = 9.000 recurring
9*x = 9 implies x = 1.

Don'tcha just love nonunique n-ary representation?

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nicolyrezk December 14 2006, 14:10:49 UTC
I do, actually. I used to be a maths geek.

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schivnorr December 14 2006, 15:25:26 UTC
High-5! _O/\o_

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nicolyrezk December 14 2006, 15:28:43 UTC
To give you an idea of how much of a maths geek I once was, I passed GCSE Maths (Which is at the level of your High School Diploma/GED) when I was 13. o_o;

Maaaaaaaaaaaaaaaaaths

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haggis_bagpipes December 15 2006, 03:39:18 UTC
No! 0.999 recurring does not equal 1! It equals 0.999 recurring! The difference is infinitesimal. Haha, see what I did there?

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nicolyrezk December 15 2006, 04:23:50 UTC
You're retarded, sir!

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haggis_bagpipes December 15 2006, 08:03:29 UTC
constantly!

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I think you'll appreciate this. haggis_bagpipes December 29 2006, 21:10:37 UTC
If a = b = 1

then a2 = ab

so a2 - b2 = ab - b2

and so (a + b) (a - b) = b (a - b)

therefore a + b = b

1 + 1 = 1

2 = 1

Holy shit, let's go through that again, substituting a and b with 1!

If a = b = 1

then 12 = 1x1
(1 = 1)

so 12 - 12 = 1x1 - 12
(1 - 1 = 1 - 1)
(0 = 0)

Aha!

and so (1 + 1) (1 - 1) = 1 x (1 - 1)
(2) x (0) = 1 x (0)
0 = 0

therefore (1 + 1) = 1
What happened between this step and the last one?

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