I'm in the midst of a head cold, so my brain isn't working so well right now. I'm hoping you can at least confirm the answer I've come up with. *sigh
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The pattern you describe of P3k2 doesn't require an odd number of stitches, it requires one which is divisible by 5 (so it could be either odd or even).
I agree that if the pattern bit between the border is essentially in 5 stitch blocks i.e. p3 k2 then the pattern bit should be in multiples of 5. And I agree that comes to 133 stitches. However, I don't understand how that pattern would have worked with 71 stitches, because 71 - 8 = 63, and 65 divided by 5 doesn't go - you end up with 3 extra stitches. So, is there something extra that is done between the borders?
Because 63 isn't divisible by 5, I think you need to look at exactly what has to be done in the pattern part between the borders and work it out from there i.e. check whether there is other stuff you would or would not double.
By all means describe it and I'll try to check your working!!
As soon as I read your post this morning, I realized I was making this WAY harder than I should have. I know my brain was on the tip of the answer last night because I said to myself " It would be better if the border just didn't exist".
I just looked at the pattern, and I'm a maroon. :P You were completely right and after the P3,K2 repeat, there's another P3 right before the border. Which - just with the 63 alone DOES work, because you have the 60 divisible by 5, then you have the P3. I never see it because my brain says "You just p3, k2 till you get to the last four stitches".
Which means I simply screwed up the row.
Can we pretend this post never happened? :-) Thank you. I'm off to take my Nasonex and knit till the Ravens win the Superbowl. :-)
Although - do you want to add another 3 stitches to your needles so that you can still end the row with P3 before the border? - it sounds as though the design likes P3 next to the border, rather than K2. You should have a multiple of 5 (125) +3 (128) + 4 + 4 = 136 stitches. That way you can border 4, (p3K2) to last 7 stitches, P3, border 4.
(And I thought you said you were taking Nanosex!! you don't want to see my Google results...)
I had to go back to my post to make sure I hadn't misspelled it! I'm sure that would cure anything, wouldn't it? I won't be able to unsee that now everytime I look at the packaging!!
Sorry, I meant to say basically repeat the P3, k2 to the border, but obviously ending on a P3. I always stop a few stitches before the border to make sure I've been counting correctly (HA!) before I get to the last four. If I end up with a weird number (5, or 6 for example), I know somewhere along the way I've goofed.
I know what I did now: 63 x 2 + 4 + 4 = 134 (my original number), when I was only supposed to do: 60 x 2 +3 + 4 + 4 = 131. Add another 5 (another repeat of p3, k2) in there and that makes it 136. I must be getting better because that actually makes sense!
Comments 5
I agree that if the pattern bit between the border is essentially in 5 stitch blocks i.e. p3 k2 then the pattern bit should be in multiples of 5. And I agree that comes to 133 stitches. However, I don't understand how that pattern would have worked with 71 stitches, because 71 - 8 = 63, and 65 divided by 5 doesn't go - you end up with 3 extra stitches. So, is there something extra that is done between the borders?
Because 63 isn't divisible by 5, I think you need to look at exactly what has to be done in the pattern part between the borders and work it out from there i.e. check whether there is other stuff you would or would not double.
By all means describe it and I'll try to check your working!!
Reply
I just looked at the pattern, and I'm a maroon. :P You were completely right and after the P3,K2 repeat, there's another P3 right before the border. Which - just with the 63 alone DOES work, because you have the 60 divisible by 5, then you have the P3. I never see it because my brain says "You just p3, k2 till you get to the last four stitches".
Which means I simply screwed up the row.
Can we pretend this post never happened? :-) Thank you. I'm off to take my Nasonex and knit till the Ravens win the Superbowl. :-)
Reply
Although - do you want to add another 3 stitches to your needles so that you can still end the row with P3 before the border? - it sounds as though the design likes P3 next to the border, rather than K2. You should have a multiple of 5 (125) +3 (128) + 4 + 4 = 136 stitches. That way you can border 4, (p3K2) to last 7 stitches, P3, border 4.
(And I thought you said you were taking Nanosex!! you don't want to see my Google results...)
Reply
Sorry, I meant to say basically repeat the P3, k2 to the border, but obviously ending on a P3. I always stop a few stitches before the border to make sure I've been counting correctly (HA!) before I get to the last four. If I end up with a weird number (5, or 6 for example), I know somewhere along the way I've goofed.
I know what I did now: 63 x 2 + 4 + 4 = 134 (my original number), when I was only supposed to do: 60 x 2 +3 + 4 + 4 = 131. Add another 5 (another repeat of p3, k2) in there and that makes it 136. I must be getting better because that actually makes sense!
Thank you so much for your help!
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