HELP!! need it by tomorrow!

Dec 14, 2006 21:03

Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This means that the masses of the two stars are equal. If the orbital velocity of each star is 220 km/s and the orbital period of each is 14.4 days, find the mass M of each star.

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Comments 12

mjhamilton December 15 2006, 03:22:36 UTC
Think about the centripetal force and the gravitational force.

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yayforyeh December 15 2006, 03:24:29 UTC
yes. but the masses cancel out!

(GMm)/r^2 = (Mv^2)/r

so i found the mass of the thing it's rotating around...but if you plug that in..the Ms (which you need to find) go away

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cthulhu_dream December 15 2006, 03:28:35 UTC
No, just solve for m.

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mjhamilton December 15 2006, 03:30:44 UTC
m = M

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cthulhu_dream December 15 2006, 03:26:27 UTC
Start with Newton's universal law of gravitation, aka F(grav) = G*M*m/R^2
In this case, M = m, G you can look up, and R is the distance between M and m.

Remember also that F(centripetal) = mv^2/r
Here r is the distance to the center of mass of the binary system.

You are given the period, so you can easily work out r using v = r*omega where omega is the radial frequency of rotation. You are given the period of rotation, so finding omega is easy.

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