Dec 14, 2006 21:03
Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This means that the masses of the two stars are equal. If the orbital velocity of each star is 220 km/s and the orbital period of each is 14.4 days, find the mass M of each star.
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(GMm)/r^2 = (Mv^2)/r
so i found the mass of the thing it's rotating around...but if you plug that in..the Ms (which you need to find) go away
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In this case, M = m, G you can look up, and R is the distance between M and m.
Remember also that F(centripetal) = mv^2/r
Here r is the distance to the center of mass of the binary system.
You are given the period, so you can easily work out r using v = r*omega where omega is the radial frequency of rotation. You are given the period of rotation, so finding omega is easy.
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