[ Lookie here, check out this gorgeous view of the sea. The way the water is so clear and the sun shining brightly down on it. It seems like the perfect day for a swim and the perfect day to be outside, especially on the beach. Those by the Cianwood and Olivine beach should get out right now and sit right there, just like what the good old
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I mean. Uh. Junpei happens to have skills in this area....so if he mentally makes two equations, y=4x and y+20=2(x+20), and he plugs the value of 4x in for y in the second equation.... ]
The little girl's ten, right? And the dad's four times that, so forty.
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That is correct! When the father is sixty, he will be twice as old as his daughter who will be thirty by then. Very well done, my boy.
Perhaps that one has been too easy for you?
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I'm pretty good at puzzles like this, I guess. Got any more?
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Yes, I have quite the list of them. Perhaps this one is a bit harder for you. It is worth twenty-five picarats:
"Two days ago, a boy was seventeen years old. The next year, he will be twenty. How is this possible?"
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Seventeen....twenty....hmm.
[ Going to grab a piece of paper so he can visually map this out. ]
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[ And Layton is going to stay quiet. Take your time, Junpei. ]
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So if the kid's birthday was yesterday, then he was 17 two days ago and 18 the next day. But a year after that would only make the kid 19. Where did the extra year come from?
It takes him a few tries of scribbling out possibilities to settle upon an answer. ]
If his birthday was yesterday, and today was New Year's Day.....then it works, right?
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[ And hoho, look at this smile on this professor's face. ] Can you explain how it will in detail?
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Uh...so, two days ago he was 17, right? But then yesterday he turned 18. And, if today was New Year's Day, then next year he'd be turning 20, because he'll be turning 19 in December of this year.
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