Glad I waited...

[pyffe]

I had planned to go over to the college today to take the last of the regular Exams. But as I was working on the practice problems, it turns out I'd missed a section in one chapter. Specifically, Heron's Area Formula

Comments

[says_bomb]

Hmm...If you are given an acute angle and 2 sides, if the angle is between the sides (Side-Angle-Side), there's only one possible triangle. If you're given Angle-Side-Side, there may be one or two possible triangles, so I assume that's the problem you're talking about.

That means you know Angle a, Side A, and Side B. Use the law of sines to find Angle b: sin(a)/A=sin(b)/B ==> b1 = Arcsin(B/A * sin(a)). Keep in mind that the Arcsin gives you the smallest of an infinite number of solutions. so b2=180-b1 may also be a valid solution. (All the other solutions would give you an angle greater than 180, which is impossible for a triangle.)

(Lastly, Angle c = 180-a-b, and then use the law of sines to find Side C.)

[davew0071]

Well, it's all Greek to this poor math-impaired numpty.

But good luck on the test! I'm betting you get another A.

[pyffe]

Thanks for the vote of confidence. I'm feeling pretty good about it. B at the least, I hope!

[flugvogel]

Good luck, good luck, good luck!