Comments | rabidplaid: yesyes indeed.

rabidplaid

yesyes indeed.

Feb 23, 2007 23:40

this vacation has been spent with equal amounts of time playing snood, waiting, and repeating oh god oh god oh god oh god in my head ( Read more... )

Comments 6

le_oh_crocs February 25 2007, 17:51:15 UTC

liz has such expressive hands

le_oh_crocs February 25 2007, 17:51:39 UTC

ps i wrote espresso hands and had to erase it

rabidplaid February 25 2007, 18:44:00 UTC

espresso hands could probably be used to successfully take over the world. except not me, coffee is like the sun to me, painful and everywhere i look.

xxdidoxx February 27 2007, 01:50:58 UTC

alex cann you help me with this problem PLEASE?!?!?

the integral of x squared over the square root of one minus x. dx. im supposed to use substitution.

rabidplaid February 27 2007, 02:45:58 UTC

alright, i could be totally making this up (most likely) but i got -2x^2(1-x)^(1/2) - (8/3)x(1-x)^(3/2) - (16/15)(1-x)^(5/2)

you know u and v substitutions, right? (or i dunno if you call them that) so then u=x^2 and dv=(1-x)^(-1/2) so du=2x and v=-2(1-x)^(1/2). if you plug those into the uv - integral of vdu, then you'll get another integral that you have to use the substitutions in. does that make any sense?

chances are though that i'm completely wrong and there's actually a much more simple, logical way to do it, in which case i'll feel really dumb, but you know.

xxdidoxx February 27 2007, 03:02:09 UTC

we only know the "u" substitution, i guess. we only substitute one variable at a time and differentiate it and then substitute u and du in and it usually works but i don't see any one thing to substitute AHH??
p.s. THANKS for trying!!! <3<3<3<3