Sep 11, 2008 06:51
What is 23*302 if the following is true
0+0=1
0+1=2
0+2=3
0+3=00
0+00=01
0+01=02
0+02=03
0+03=10
0+10=11
1+0=2
1+1=3
1+2=00
1+3=01
1+00=02
1+01=03
1+02=10
1+03=11
0*0=0
0*1=1
0*2=2
0*3=3
0*00=00
1*0=1
1*1=00
1*2=10
1*3=20
1*00=30
2*0=2
2*1=10
2*2=30
2*3=010
2*00=030
3*0=3
3*1=20
3*2=010
3*3=100
3*00=130
and so on...
if you don't like this, just skip it
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My answer may be wrong; when I tried doing it again, I got some results that suggest that ASSOCIATIVITY may not work the same way, i.e., (a+b)+c may not be the same as a+(b+c)... Of course, that could just be my screwup.
What's interesting is that we don't seem to have an identity (equivalent to normal 0) for +, although we do have one (equivalent to normal 1) for *. However, what's give does suggest that there SHOULD be an identity for +.
ETA 9/24 09:44 EDT:
There doesn't appear to be a zero-equivalent glyph at all; that means that it can't be a pure place-value system, and about the only way to get the answer is going to be working out the tables that were started with the givens.
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ratlan, I won't give away my spoilers on this unless/until you say it's OK to do so. As near as I can figure, they're very spoily, to the point where just giving them would lead anyone moderately skilled in math right to the answer.
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So, using * for 'ten', we'd have 5+5=*, 2x5=*, and we'd count 1,2,3,4,5,6,7,8,9,*,11,...19,1*,21...
CLUE 2: The riddle, as given, shows us ALL of the glyphs used in the counting system.
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