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Proof is the idol that tortures the pure mathematician.
On another note, the integers are formed from equivalence classes of ordered pairs on the natural numbers.
Classes have been good. I'm a little burned out from school. I'm pretty much looking forward to summer and activities other than math. Like soccer and bikes. Maybe even going topless in ( Read more... )
On another note, the integers are formed from equivalence classes of ordered pairs on the natural numbers.
Classes have been good. I'm a little burned out from school. I'm pretty much looking forward to summer and activities other than math. Like soccer and bikes. Maybe even going topless in ( Read more... )
Comments 3
I'm a friend of a friend and I'd like to make a guess at your math question:
¶ There are 366 different possibilities for birthdays. So, if we assume that the first 366 people were all born on each possible day (including February 29), this leaves 34 people who must share a birthday with someone else.
¶ So, the probability is at least 34/366 -- because there is a minimum of 34 people who will have a birthday on the same day as some one else.
¶ As a percentage, this would be approximately 9.3%
Expressed as odds, this would be approximately 10.75 to 1.
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I'm definitely curious what the answer is.
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But I'm a afraid it's not correct. Looking at your analysis, you were on the right track in the beginning! But it's actually easier than that.
Google the "Pigeon hole principle" and "the birthday problem" if your curious about the answer, it's very counter-intuitive.
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A quick check at Wikipedia shows me that I started off good, but over analyzed the problem. But I won't give away the answer to see if someone can come up with it on their own.
I will say this, though, I like mind puzzles like this -- keeps the brain cells active. :D
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