Not that anyone who reads this would care,

[sombragris]

but I just stumbled upon another nifty property:

In the expansion of (x1 + x2 + x3 + x4 + ... + xi)n

the coefficient of the term with (x1a1)(x2a2) ... (xiai)

equals n!/((a1!)(a2!)...(an!))

(thanks,

Comments

[prophet_elisha]

You're right.

[sombragris]

i think that's the first time you've ever said that to me.

[prophet_elisha]

I think that's the first time you've ever been right. :P

[blargh88]

hmm the question now becomes...how did you "stumble" upon that lol?

i'm guessing project euler? :P

[aznstrawbeary]

dudeeee that's cool!