If you roll a bowling ball down the alley (assuming it rolls straight), when it begins rolling without sliding it will be moving at 5/7 its original velocity.
What is the velocity of the bowling ball after it has completed its arc through the air, after leaving Samantha's hand and crashing into the floorboards?
This is great. Now that you're at MIT maybe you can answer a question that has perplexed thousands for decades. What IS the airspeed velocity of an unladen swallow?
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2)center of mass at geometric center
3)ball rolls straight
but valid assumptions!
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v = velocity upon rolling
KE = KE + RE
(1/2)mV^2 = (1/2)mv^2 + (1/2)Iw^2
= (1/2)mv^2 + (1/2)[(2/5)mR^2](v^2/R^2)
= (1/2)mv^2 + (1/5)mv^2
= (7/10)mv^2
so (1/2)V^2 = (7/10)v^2
v^2 = (1/2)V^2/(7/10)
v^2 = (5/7)V^2
v = Sqrt(5/7)V
Tell me if i did something dumb...
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african or european?
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Did you feel the earthquake?
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