Uber-crazy-nuts C# puzzle
Puzzle
Write a C# program which
My solution requires the /unsafe compiler switch to be set.
using System; public class Experiment { // This must be "struct", otherwise it's not nullable public struct G { } // This must be "Action" to be compatible with ()=>{;} public class X { public Action x; } // This needs a getter and setter for <<= to be applicable public int this[X[] t] { get { return 47; } set { } } // This needs to be marked 'unsafe' in order to use pointer types public unsafe void Blah() { byte b = 5; // This needs to be of a pointer type for the unary '*' operator to be applicable byte* a = &b; // This is the magic line! this[new[] { new X { x = (Action) (object) default(G?>[,])??(()=>{;}),},}]<<=!(~+-*++a > 0) ? 0 : 0; } // It needs a Main method, otherwise it doesn't compile public static void Main() { } }
Write a C# program which
- compiles without errors or warnings under some set of compiler options;
- contains the following sequence of characters: ?>?>[,])??(()=>{;}),},}]<<=!(~+-*++
- does not contain any string literals or comments
- it doesn't have to do anything useful
My solution requires the /unsafe compiler switch to be set.
using System; public class Experiment { // This must be "struct", otherwise it's not nullable public struct G { } // This must be "Action" to be compatible with ()=>{;} public class X { public Action x; } // This needs a getter and setter for <<= to be applicable public int this[X[] t] { get { return 47; } set { } } // This needs to be marked 'unsafe' in order to use pointer types public unsafe void Blah() { byte b = 5; // This needs to be of a pointer type for the unary '*' operator to be applicable byte* a = &b; // This is the magic line! this[new[] { new X { x = (Action) (object) default(G?>[,])??(()=>{;}),},}]<<=!(~+-*++a > 0) ? 0 : 0; } // It needs a Main method, otherwise it doesn't compile public static void Main() { } }