Hey all you math types!
I have two math problems that are proving to be difficult. If anyone could show me how to solve them I'd appreciate it!
1. 2e^(-2x) - 3e^(-x) + 1 = 0
^ = raised to the power of.
I keep getting x = -0.405 which works without the + 1. Not sure where I'm messing up as I am dragging the 1 to the RHS and - ln1 = 0
2.
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2. The first question is obviously 3/13 chance of drawing a face card.
For the second card, there is a 1/13 chance you drew a queen and a 12/13 chance you didn't. If you drew a queen, theres a 3/51 or 1/17 chance of drawing another. If you didn't draw a queen, there's a 4/51 chance of drawing a queen. Multiply the probabilities, so:
(1/13)*(1/17) + (12/13)*(4/51) = (1/221) + (48/663) = 17/221.
I think their number is wrong.
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Assuming n = e^-x, we can rewrite the question as:
2n^2 - 3n + 1 = 0
We can expand this quadratic equation as:
(2n - 1)(n - 1) = 0
In order to have this product be zero either bracket can equal zero, meaning we have two answers:
(2n - 1) = 0
(n - 1) = 0
Therefore, the two answers are:
e^(-x) = 1/2 == x = -ln(1/2)
e^(-x) = 1 == x = -ln1
The two answers are x = 0 and x ≈ 0.693
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x~0.693 doesn't seem to work on the calc. I'll play tho - thanks.
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If the first is not a queen and the second is a queen that's:
8/52*4/51
If they are both queens:
4/52*3/51
Add them up and reduce you get 44/2652 to 11/663
Big sigh of relief - thanks!
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Thanks for all the help!
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