5th grade math problem

[stephne84]

help please.

so you draw a regular figure with 100 sides (sides are all the same length, angles are all the same). you draw another regular figure with the same length of sides, but instead of 100 sides, you draw 250 sides. what is the ratio between the areas of the two figures?

this may be for fifth grade, but im just that dumb.

Comments

[humor_yourself]

So i asked a friend about this. He is absolutely brillant at math. This is what he came up with. I added the end

Friend: basically, take the "center" of the figure and divide it into 100 or 250 triangles.

Friend: then 100*(area of a triangle, with angle 360/100) divided by 250 *(area of a triangle with angle 360/250)

Me: hmmmm....i could see dividing each triangle into two seperate triangles with a right angle and, assuming each outside one = 1, or 2 or whatever finding the area of the triangle and multiplying by 200 or 500

If you need any more help i could solve it from here if needed

[humor_yourself]

Oh and you aren't dumb! I couldn't figure it out and i'm minoring in the damn subject! ( =

[s0meb0dyt0ldme]

I started to draw the 100 side figure but I ran out of paper. sorry.

[ruiez]

why are you doing fifth grade math problems in the first place?? did i miss something again?? :)