a tough probability problem

Oct 09, 2010 17:49

I'm working on my hash function test suite, and I've hit a difficult problem in statistics/probability that I can't find a good answer to, so I'm documenting it here ( Read more... )

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hexapod October 10 2010, 01:57:38 UTC
I thought about this for 2 minutes and have no solution... but a possible insight:

A_fair and B_fair are independent situations. You should be able to compare

P(A_fair) = P(A_fair && 4hA) + P(A_fair && 3hA) + P(A_fair && 2hA) + P(A_fair && hA)

and similar for P(B_fair).

3 Lagunitas IPAs is too many for me to do the math myself... or even to discern whether I'm really making sense.

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