More math fun..

[timeimp]

Given that a and b are integers such that a = b + 1,
a = b + 1
(a-b)a = (a-b)(b+1)
a2 - ab = ab + a - b2 - b
a2 - ab -a = ab + a -a - b2 - b
a(a - b - 1) = b(a - b - 1)
a = b
b + 1 = b
Therefore, 1 = 0

AND

Given that a and b are integers such that a = b
a = b
a - b - 2 = a - b - 2
a(a - b - 2) = b(a - b - 2)
a2 - ab - 2a = ab -

Comments

I like this one

[cmeador]

1 + -1 + 1 + -1 + 1 + -1 + 1 + -1 + ... = ?

(1 + -1) + (1 + -1) + (1 + -1) + (1 + -1) + ... = 0

1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + (-1 + 1) + ... = 1

1 + -1 + 1 + -1 + 1 + -1 + 1 + -1 + ... = S
S = 1 - (1 + -1 + 1 + -1 + 1 + -1 + 1 + -1 + ...)
S = 1 - S
S = 1/2

fact: This series can be rearranged so that it converges to any sum that you want. http://en.wikipedia.org/wiki/Riemann_series_theorem

[dulzura_implaca]

Hey, it's phoebe. Is your dad an independent plumber or is he with a company? We need help. :(

Bad corroded p-trap. bad bad bad

[timeimp]

He works for Ray Baker Heating and Plumbing. 2 of my cousins for there too.

They should be in the yellow pages.

[dulzura_implaca]

awesome. we'll give them a call!