Given that a and b are integers such that a = b + 1,
a = b + 1
(a-b)a = (a-b)(b+1)
a2 - ab = ab + a - b2 - b
a2 - ab -a = ab + a -a - b2 - b
a(a - b - 1) = b(a - b - 1)
a = b
b + 1 = b
Therefore, 1 = 0
AND
Given that a and b are integers such that a = b
a = b
a - b - 2 = a - b - 2
a(a - b - 2) = b(a - b - 2)
a2 - ab - 2a = ab -
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